Commit 9e6e003e authored by Adam Jackson's avatar Adam Jackson 🎧 Committed by Matt Turner
Browse files

Fix build on i686

Presumably this only matters for i686 because amd64 implies sse2, but:

BUILDSTDERR: In file included from gen4_vertex.c:34:
BUILDSTDERR: gen4_vertex.c: In function 'emit_vertex':
BUILDSTDERR: sna_render_inline.h:40:26: error: inlining failed in call to always_inline 'vertex_emit_2s': target specific option mismatch
BUILDSTDERR:  static force_inline void vertex_emit_2s(struct sna *sna, int16_t x, int16_t y)
BUILDSTDERR:                           ^~~~~~~~~~~~~~
BUILDSTDERR: gen4_vertex.c:308:25: note: called from here
BUILDSTDERR:  #define OUT_VERTEX(x,y) vertex_emit_2s(sna, x,y) /* XXX assert(!too_large(x, y)); */
BUILDSTDERR:                          ^~~~~~~~~~~~~~~~~~~~~~~~
BUILDSTDERR: gen4_vertex.c:360:2: note: in expansion of macro 'OUT_VERTEX'
BUILDSTDERR:   ^~~~~~~~~~

The bug here appears to be that emit_vertex() is declared 'sse2' but
vertex_emit_2s is merely always_inline. gcc8 decides that since you said
always_inline you need to have explicitly cloned it for every
permutation of targets. Merely saying inline seems to do the job of
cloning vertex_emit_2s as much as necessary.

So to reiterate: if you say always-inline, it won't, but if you just say
maybe inline, it will. Thanks gcc, that's helpful.
parent 3a2dec17
......@@ -32,7 +32,7 @@
#define likely(expr) (__builtin_expect (!!(expr), 1))
#define unlikely(expr) (__builtin_expect (!!(expr), 0))
#define noinline __attribute__((noinline))
#define force_inline inline __attribute__((always_inline))
#define force_inline inline /* __attribute__((always_inline)) */
#define fastcall __attribute__((regparm(3)))
#define must_check __attribute__((warn_unused_result))
#define constant __attribute__((const))
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